Optimal. Leaf size=193 \[ 77 c^2 d^{13/2} \left (b^2-4 a c\right )^{3/4} \tan ^{-1}\left (\frac{\sqrt{d (b+2 c x)}}{\sqrt{d} \sqrt [4]{b^2-4 a c}}\right )-77 c^2 d^{13/2} \left (b^2-4 a c\right )^{3/4} \tanh ^{-1}\left (\frac{\sqrt{d (b+2 c x)}}{\sqrt{d} \sqrt [4]{b^2-4 a c}}\right )-\frac{11 c d^3 (b d+2 c d x)^{7/2}}{2 \left (a+b x+c x^2\right )}-\frac{d (b d+2 c d x)^{11/2}}{2 \left (a+b x+c x^2\right )^2}+\frac{154}{3} c^2 d^5 (b d+2 c d x)^{3/2} \]
[Out]
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Rubi [A] time = 0.404011, antiderivative size = 193, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.269 \[ 77 c^2 d^{13/2} \left (b^2-4 a c\right )^{3/4} \tan ^{-1}\left (\frac{\sqrt{d (b+2 c x)}}{\sqrt{d} \sqrt [4]{b^2-4 a c}}\right )-77 c^2 d^{13/2} \left (b^2-4 a c\right )^{3/4} \tanh ^{-1}\left (\frac{\sqrt{d (b+2 c x)}}{\sqrt{d} \sqrt [4]{b^2-4 a c}}\right )-\frac{11 c d^3 (b d+2 c d x)^{7/2}}{2 \left (a+b x+c x^2\right )}-\frac{d (b d+2 c d x)^{11/2}}{2 \left (a+b x+c x^2\right )^2}+\frac{154}{3} c^2 d^5 (b d+2 c d x)^{3/2} \]
Antiderivative was successfully verified.
[In] Int[(b*d + 2*c*d*x)^(13/2)/(a + b*x + c*x^2)^3,x]
[Out]
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Rubi in Sympy [A] time = 96.2499, size = 196, normalized size = 1.02 \[ 77 c^{2} d^{\frac{13}{2}} \left (- 4 a c + b^{2}\right )^{\frac{3}{4}} \operatorname{atan}{\left (\frac{\sqrt{b d + 2 c d x}}{\sqrt{d} \sqrt [4]{- 4 a c + b^{2}}} \right )} - 77 c^{2} d^{\frac{13}{2}} \left (- 4 a c + b^{2}\right )^{\frac{3}{4}} \operatorname{atanh}{\left (\frac{\sqrt{b d + 2 c d x}}{\sqrt{d} \sqrt [4]{- 4 a c + b^{2}}} \right )} + \frac{154 c^{2} d^{5} \left (b d + 2 c d x\right )^{\frac{3}{2}}}{3} - \frac{11 c d^{3} \left (b d + 2 c d x\right )^{\frac{7}{2}}}{2 \left (a + b x + c x^{2}\right )} - \frac{d \left (b d + 2 c d x\right )^{\frac{11}{2}}}{2 \left (a + b x + c x^{2}\right )^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((2*c*d*x+b*d)**(13/2)/(c*x**2+b*x+a)**3,x)
[Out]
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Mathematica [A] time = 1.30729, size = 210, normalized size = 1.09 \[ (d (b+2 c x))^{13/2} \left (\frac{4 c^2 \left (77 a^2+121 a c x^2+32 c^2 x^4\right )+b^2 c \left (71 c x^2-33 a\right )+4 b c^2 x \left (121 a+64 c x^2\right )-3 b^4-57 b^3 c x}{6 (b+2 c x)^5 (a+x (b+c x))^2}+\frac{77 c^2 \left (b^2-4 a c\right )^{3/4} \tan ^{-1}\left (\frac{\sqrt{b+2 c x}}{\sqrt [4]{b^2-4 a c}}\right )}{(b+2 c x)^{13/2}}-\frac{77 c^2 \left (b^2-4 a c\right )^{3/4} \tanh ^{-1}\left (\frac{\sqrt{b+2 c x}}{\sqrt [4]{b^2-4 a c}}\right )}{(b+2 c x)^{13/2}}\right ) \]
Antiderivative was successfully verified.
[In] Integrate[(b*d + 2*c*d*x)^(13/2)/(a + b*x + c*x^2)^3,x]
[Out]
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Maple [B] time = 0.024, size = 857, normalized size = 4.4 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((2*c*d*x+b*d)^(13/2)/(c*x^2+b*x+a)^3,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((2*c*d*x + b*d)^(13/2)/(c*x^2 + b*x + a)^3,x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.243336, size = 1173, normalized size = 6.08 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((2*c*d*x + b*d)^(13/2)/(c*x^2 + b*x + a)^3,x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((2*c*d*x+b*d)**(13/2)/(c*x**2+b*x+a)**3,x)
[Out]
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GIAC/XCAS [A] time = 0.269915, size = 703, normalized size = 3.64 \[ -\frac{77}{2} \, \sqrt{2}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{3}{4}} c^{2} d^{5} \arctan \left (\frac{\sqrt{2}{\left (\sqrt{2}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{1}{4}} + 2 \, \sqrt{2 \, c d x + b d}\right )}}{2 \,{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{1}{4}}}\right ) - \frac{77}{2} \, \sqrt{2}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{3}{4}} c^{2} d^{5} \arctan \left (-\frac{\sqrt{2}{\left (\sqrt{2}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{1}{4}} - 2 \, \sqrt{2 \, c d x + b d}\right )}}{2 \,{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{1}{4}}}\right ) + \frac{77}{4} \, \sqrt{2}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{3}{4}} c^{2} d^{5}{\rm ln}\left (2 \, c d x + b d + \sqrt{2}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{1}{4}} \sqrt{2 \, c d x + b d} + \sqrt{-b^{2} d^{2} + 4 \, a c d^{2}}\right ) - \frac{77}{4} \, \sqrt{2}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{3}{4}} c^{2} d^{5}{\rm ln}\left (2 \, c d x + b d - \sqrt{2}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{1}{4}} \sqrt{2 \, c d x + b d} + \sqrt{-b^{2} d^{2} + 4 \, a c d^{2}}\right ) + \frac{64}{3} \,{\left (2 \, c d x + b d\right )}^{\frac{3}{2}} c^{2} d^{5} + \frac{2 \,{\left (15 \,{\left (2 \, c d x + b d\right )}^{\frac{3}{2}} b^{4} c^{2} d^{9} - 120 \,{\left (2 \, c d x + b d\right )}^{\frac{3}{2}} a b^{2} c^{3} d^{9} + 240 \,{\left (2 \, c d x + b d\right )}^{\frac{3}{2}} a^{2} c^{4} d^{9} - 19 \,{\left (2 \, c d x + b d\right )}^{\frac{7}{2}} b^{2} c^{2} d^{7} + 76 \,{\left (2 \, c d x + b d\right )}^{\frac{7}{2}} a c^{3} d^{7}\right )}}{{\left (b^{2} d^{2} - 4 \, a c d^{2} -{\left (2 \, c d x + b d\right )}^{2}\right )}^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((2*c*d*x + b*d)^(13/2)/(c*x^2 + b*x + a)^3,x, algorithm="giac")
[Out]